![]() Given n, put the integers in a random order. It is for instructional purposes If you want to get a random permutation of integers randperm will help. If there is only one character in the aracter array, the function should give that character back twice since it is both the first and last character of the aracter array ample: stringfirstandlast('boring example') be" Turn the first and last characters of a character array, concatenated together. Return 1 if number a exists in vector b otherwise return O. Given a vector, vec, return the indices where vec is greater than scalar, thresh. The difference is this: vec und thresh vi 25 (vec > thresh) vi 1 What we are looking for now is how to get the values 4 Because those are the indices where the binary comparison is true. This exercise is for finding the index of indices that meet your criteria. You may already know how to find the logical indices of the elements of a vector that meet your criteria. Yes, this looks hard and it is indeed hard! To check if you understand thoroughly, try predicting a square Matrix's similar different permutations.This is a basic MATLAB operation. So, there will be 1 4x2 (4x2x1) matrix(itself!). * G = permute(A,) % this makes no difference, using to show the reasoningĤx2x1 ( row(1) dimension of A = 4, column(2) dimension of A = 2, page(3) dimension of A = 1 4 is row dimension, 2 is column dimension and 1 is page dimension for the generated G) * F = permute(A,) % this is transpose and same as Ģx4x1 ( column(2) dimension of A = 2, row(1) dimension of A = 4, page(3) dimension of A = 1 2 is row dimension, 4 is column dimension and 1 is page dimension for the generated F) So, there will be 4 2x1 (2x1x4) column matrixes. As in: ans(:,:,1) =Ģx1x4 ( column(2) dimension of A = 2, page(3) dimension of A = 1, row(1) dimension of A = 4 2 is row dimension, 1 is column dimension and 4 is page dimension for the generated E) So, there will be 2 4x1 (4x1x2) column matrixes. As in: ans(:,:,1) =Ĥx1x2 ( row(1) dimension of A = 4, page(3) dimension of A = 1, column(2) dimension of A = 2 4 is row dimension, 1 is column dimension and 2 is page dimension for the generated D) So, there will be 2 1x4 (1x4x2) row matrixes. At this point, we have to make the permutations of only one digit with the index 3 and it has only one permutation i.e., itself. Similarly, permutation(3,3) will be called at the end. And thus, permutation(2,3) will be called to do so. As in: ans(:,:,1) =ġx4x2 ( page(3) dimension of A = 1, row(1) dimension of A = 4, column(2) dimension of A = 2 1 is row dimension, 4 is column dimension and 2 is page dimension for the generated C) Now in this permutation (where elements are 2, 3 and 4), we need to make the permutations of 3 and 4 first. So, there will be 4 1x2 (1x2x4) row matrixes. G = permute(A,) % means ġx2x4 ( page(3) dimension of A = 1, column(2) dimension of A = 2, row(1) dimension of A = 4 1 is row dimension, 2 is column dimension and 4 is page dimension for the generated B. % 3 = page, 2 = column and 1 = row dimensions):ī = permute(A,) % means Ĭ = permute(A,) % means ĭ = permute(A,) % means Į = permute(A,) % means į = permute(A,) % means % (numbers in the order argument of permute function indicates dimensions, Now let's move to the examples, Finally: % A has 4 rows, 2 columns and 1 page Order argument passed to permute swap these dimensions in the matrix and produce an awkward combination of arrays, I think permute is a misnomer for this effect. B=zeros(10,3) has 10 rows, 3 columns and 1 page, this order is important!) And if you don't specify a dimension, its default count is set to 1. Here are some examples to prevent you from suffering a similar excruciating pain:įirst, let's remember the dimensions' names of matrix in matlab: A = zeros(4,5,7), matrix A has 4 rows, 5 columns and 7 pages. Therefore, I used the F*ck word many times during " my journey of understanding the permute function". Wow, this is one of the hardest functions to figure out among all the different SDKs I have used up to now.
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